Factorise : $3 x y - 6 z y - 3 x t + 6 z t$

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Solution

Given that: $3 x y - 6 z y - 3 x t + 6 z t$
$= (3 x y - 6 z y) + (- 3 x t + 6 z t)$ , group pair of terms
$= 3 y (x - 2 z) - 3 t (x - 2 z)$ , factor each binomials
$= (x - 2 z) (3 y - 3 t)$ , factor out common factor $(x - 2 z)$
The factors of $3 x y - 6 z y - 3 x t + 6 z t$ are $(x - 2 z) (3 y - 3 t)$

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