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Question

Factorise: 4x2+12xy+9y2x8x12y

A
(2x3y)(2x+3y2)
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B
(2x3y)(2x3y4)
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C
(2x+3y)(3x+2y4)
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D
(2x+3y)(2x+3y4)
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Solution

The correct option is D (2x+3y)(2x+3y4)
4x2+12xy+9x28x12y=(2x)2+2×2x×3y+(3y)28x12y=(2x+3y)28x12y[(a+b)2=a2+2ab+b2]=(2x+3y)24(2x+3y)=(2x+3y)(2x+3y4)

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