Factorise: 4(x-y)^2-12(x-y)+9

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Solution

Take (x-y) as ‘a’
then given equation becomes
4a^2-12a+9
4a^2-6a-6a+9
2a (2a-3)-3 (2a-3)
(2a-3)(2a-3)
Resubstituting (x-y) for ‘a’
[2(x-y)-3][2(x-y)-3]
(2x-2y-3)(2x-2y-3)
(2x-2y-3)^2

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Similar questions

4 x^{4} - 12 x^{2} + 9

1.Write the expansion of ( x- y ) square. Using the identity factorise 4x square-12x+9

Factorize:

$4 (x - y)^{2} + 12 (x - y) (x + y) + 9 (x + y)^{2}$

Factorise:

$3 - 5 x + 5 y - 12 (x - y)^{2}$

a^{2} + 2 a b + b^{2} = (a + b)^{2}

4 x^{2} + 12 x + 9

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