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Question

Factorise:
49(2x+3y)270(4x29y2)+25(2x3y)2

A
4(x9y)2
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B
9(x+4y)2
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C
16(x+9y)2
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D
16(x9y)2
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Solution

The correct option is C 16(x+9y)2
49(2x+3y)270(4x29y2)+25(2x3y)2
=(7(2x+3y))22×7(2x+3y)×5(2x3y)+(5(2x3y))2
=[7(2x+3y)5(2x3y)]2=[14x+21y10x+15y]2
=(4x+36y)2=(4(x+9y))2=16(x+9y)2

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