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Question

Factorise: 4a+12b

A
4(a+3b)
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B
a(4+3b)
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C
4a(1+3b)
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D
4(a+4b)
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Solution

The correct option is A 4(a+3b)
4a+12b
=(2×2×a)+(2×2×3×b)
=(2×2)(a+3×b)
=4(a+3b)

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