The correct option is A 4(a + 3b) 4a+12b = (2× 2 × a) + (2× 2× 3 × b) = (2× 2) (a + 3 × b) = 4 (a+3b) ...

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Expansion of (a ± b ± c)²

Factorise: ...

Question

Factorise: $4 a + 12 b$

4 (a + 3 b)

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a (4 + 3 b)

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4 a (1 + 3 b)

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4 (a + 4 b)

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Solution

The correct option is A $4 (a + 3 b)$
$4 a + 12 b$
$= (2 \times 2 \times a) + (2 \times 2 \times 3 \times b)$
$= (2 \times 2) (a + 3 \times b)$
$= 4 (a + 3 b)$

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= (4 a - 3 b) (4 a - 3 b) (4 a - 3 b)

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