Factorise: $4 a^{2} + 4 a b + b^{2}$

$(2 a - b) \times (2 a - b)$

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$(4 a + b) \times (4 a + b)$

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$(a + 2 b) \times (a + 2 b)$

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$(2 a + b) \times (2 a + b)$

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Solution

The correct option is D
$(2 a + b) \times (2 a + b)$

$4 a^{2} + 4 a b + b^{2} = 4 a^{2} + 2 a b + 2 a b + b^{2} = 2 a (2 a + b) + b (2 a + b) = (2 a + b) (2 a + b)$

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