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Question

Factorise: 4a2+4ab+b2


  1. (2ab)×(2ab)

  2. (4a+b)×(4a+b)

  3. (a+2b)×(a+2b)

  4. (2a+b)×(2a+b)


Solution

The correct option is D

(2a+b)×(2a+b)


4a2+4ab+b2=4a2+2ab+2ab+b2=2a(2a+b)+b(2a+b)=(2a+b)(2a+b)

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