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Question

Factorise 4a2−8ab

A
4a(a+2b)
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B
4a(ab)
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C
4a(a2b)
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D
a(a2b)
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Solution

The correct option is B 4a(a2b)
Given expression is 4a28ab.

Taking 4a common from both terms of 4a28ab, we get:
4a(a2b)

Hence, 4a28ab=4a(a2b).

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