Factorise: $4 a b x^{2} + 8 a b x + 12 a b y$

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Solution

Since in the equation $4 a b x^{2} + 8 a b x + 12 a b y$ , $4 a b$ is the common term, therefore, can be factorised as follows:

$4 a b x^{2} + 8 a b x + 12 a b y = 4 a b (x^{2} + 2 x + 3 y)$

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