Question

Factorise:
4n² − 8n + 3

Answer 1

$$\begin{gathered} Thegivenexpressionis4n^2-8n+3. \\ \mathrm{Find}\mathrm{two}\mathrm{numbers}\mathrm{that}\mathrm{follow}\mathrm{the}\mathrm{conditions}\mathrm{given}\mathrm{below}: \\ Sum=-8 \\ Product=4\times 3=12 \\ Clearly,thenumbersare-6and-2. \\ 4n^2-8n+3=4n^2-2n-6n+3 \\ =2n(2n-1)-3(2n-1) \\ =(2n-1)(2n-3) \end{gathered}$$