The correct option is C 4(x 1)^2 4x^2 8x+4 =4(x^2 2x+1) = 4 (x^2 2 × x nbsp;× nbsp;1 + 1^2) = 4 (x 1)^2 nbsp; nbsp; nbsp ...

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(a-b)^2 Expansion and Visualisation

Factorise 4...

Question

Factorise $4 x^{2} - 8 x + 4$

4 (x + 1)^{2}

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(x + 1)^{2}

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4 (x - 1)^{2}

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(x - 1)^{2}

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Solution

The correct option is C $4 (x - 1)^{2}$
$4 x^{2} - 8 x + 4$
$= 4 (x^{2} - 2 x + 1)$
$= 4 (x^{2} - 2 \times x \times 1 + 1^{2})$
$= 4 (x - 1)^{2}$ [Using: $a^{2} - 2 a b + b^{2} = (a - b)^{2}]$
$= 4 (x - 1) (x - 1)$

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