wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise:
4x2+9y2+25z2+12xy+30yz+20zx

Open in App
Solution

Now,

4x2+9y2+25z2+12xy+30yz+20zx

Using identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ac

=(2x)2+(3y)2+(5z)2+2×2x×3y+2×3y×5z+2×2x×5z

=(2x+3y+5z)2

4x2+9y2+25z2+12xy+30yz+20zx=(2x+3y+5z)(2x+3y+5z)



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon