Factorise: $4 x + b x + 4 b + b^{2}$

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Solution

The equation $4 x + b x + 4 b + b^{2}$ can be factorised as follows:

$4 x + b x + 4 b + b^{2} = (4 x + b x) + (4 b + b^{2}) = x (4 + b) + b (4 + b) = (x + b) (4 + b)$

Hence, $4 x + b x + 4 b + b^{2} = (x + b) (4 + b)$

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