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B
(5y−3)(5y−3)
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C
(2y−3)(2y−3)
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D
(2y−5)(2y−5)
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Solution
The correct option is C
(2y−3)(2y−3)
The given expression can be rewritten as, (2y)2−2(2y)(3)+32. Comparing with the identity (a−b)2=a2−2ab+b2 we get, (2y)2−2(2y)(3)+32 =(2y−3)2 =(2y−3)(2y−3)