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Question

Factorise
4y3+20y2+33y+18=0

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Solution

4y3+20y2+33y+18=0

=(y+2)[4y3+20y2+33y+18(y+2)]

=(y+2)[4y2+12y2+33y+18(y+2)]

=(y+2)[4y2+12y+9y+18(y+2)]

=(y+2)(4y2+12y+9)

=(y+2)(2y+3)(2y+3)

=(y+2)(2y+3)2

y=2,32

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