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Byju's Answer
Standard VII
Mathematics
Factors of Algebraic Expression
Factorise: 6�...
Question
Factorise:
6
(
x
−
y
)
2
–
x
+
y
–
15
(3 Marks)
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Solution
6
(
x
−
y
)
2
–
x
+
y
–
15
=
6
(
x
−
y
)
2
–
(
x
−
y
)
–
15
=
6
a
2
–
a
–
15
[
L
e
t
(
x
−
y
)
=
a
]
=
6
a
2
+
9
a
−
10
a
–
15
(1 Mark)
=
3
a
(
2
a
+
3
)
−
5
(
2
a
+
3
)
=
(
3
a
−
5
)
(
2
a
+
3
)
(1 Mark)
Replacing ‘𝑎’ by
(
x
−
y
)
, we get
=
(
3
(
x
−
y
)
−
5
)
(
2
(
x
−
y
)
+
3
)
=
(
3
x
−
3
y
−
5
)
(
2
x
−
2
y
+
3
)
(1 Mark)
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1
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Q.
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