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Question

Factorise: 6(xy)2x+y15 (3 Marks)

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Solution

6(xy)2x+y15
=6(xy)2(xy)15
=6a2a15 [Let(xy)=a]
=6a2+9a10a15 (1 Mark)
=3a(2a+3)5(2a+3)
=(3a5)(2a+3) (1 Mark)
Replacing ‘𝑎’ by (xy), we get
=(3(xy)5)(2(xy)+3)
=(3x3y5)(2x2y+3) (1 Mark)

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