1
Question
Factorise:
(6) 4x2 − 52xy + 169y2
(6) 4x2 − 52xy + 169y2
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Solution
4x2 − 52xy + 169y2
= (2x)2 − 2 × 2x × 13y + (13y)2
= (2x − 13y)2 [a2 − 2ab + b2 = (a − b)2]
= ( 2x − 13y) (2x − 13y)
∴ 4x2 − 52xy + 169y2 = (2x − 13y) (2x − 13y)
= (2x)2 − 2 × 2x × 13y + (13y)2
= (2x − 13y)2 [a2 − 2ab + b2 = (a − b)2]
= ( 2x − 13y) (2x − 13y)
∴ 4x2 − 52xy + 169y2 = (2x − 13y) (2x − 13y)
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