Question

Factorise: $6\sqrt{3}{z}^2-47z+5\sqrt{3}$

Answer 1

The given expression $6\sqrt{3}{z}^2-47z+5\sqrt{3}$ can be factorised as follows:

$6\sqrt{3}{z}^2-47z+5\sqrt{3}=6\sqrt{3}{z}^2-45z-2z+5\sqrt{3}=3\sqrt{3}z(2z-5\sqrt{3})-(2z-5\sqrt{3})=(2z-5\sqrt{3})(3\sqrt{3}z-1)$

Hence, $6\sqrt{3}{z}^2-47z+5\sqrt{3}=(2z-5\sqrt{3})(3\sqrt{3}z-1)$