Factorise: $64 m^{3} - 342 n^{3}$

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Solution

Given, $64 m^{3} - 342 n^{3}$

It should be $64 m^{3} - 343 n^{3}$

$= (4 m)^{3} - (7 n)^{2}$

$= (4 m - 7 n) ((4 m)^{2} + (4 m) (7 n) + (7 n)^{2})$

$= (4 m - 7 n) (16 m^{2} + 28 m n + 49 n^{2})$ $∵ (a^{3} - b^{3}) = (a - b) (a^{2} + a b + b^{2})$

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Similar questions

64 m^{3} - 343 n^{3}

Factorise each of the following:
(i) $27 y^{3} + 125 z^{3}$
(ii) $64 m^{3} - 343 n^{3}$

(i) 27 y^{3} + 125 z^{3}

(i i) 64 m^{3} - 343 n^{3}

Factorise each of the following:

(i)

(ii)

[Hint: See question 9.]

64 m^{3} - 343 n^{3}

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