Factorise - 64 x 3-729 y 3A- 4 x-9 y16 x2-81 y2-36 x yB- 4 x-9 y16 x2-81 y2-36 x y- 4 x-9 y16 x2-81 y2-36 x yD- 4 x-9 y16 x2-81 y2-36 x y

The correct option is A (4x 9y)(16x^2 + 81y^2 + 36xy)64x^3 729y^3 nbsp; = (4x)^3 (9y)^3 = (4x 9y) {(4x)^2 + (9y)^2 + (4x) × (9y) } = (4x 9y) (16x^2 ...

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Byju's Answer

Standard VIII

Mathematics

Factorization of a Quadratic Trinomial

Factorise : 6...

Question

Factorise : $64 x^{3} - 729 y^{3}$

(4 x - 9 y) (16 x^{2} + 81 y^{2} + 36 x y)

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(4 x + 9 y) (16 x^{2} + 81 y^{2} + 36 x y)

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(4 x - 9 y) (16 x^{2} - 81 y^{2} + 36 x y)

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(4 x - 9 y) (16 x^{2} + 81 y^{2} - 36 x y)

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Solution

The correct option is A $(4 x - 9 y) (16 x^{2} + 81 y^{2} + 36 x y)$
$64 x^{3} - 729 y^{3}$
$= (4 x)^{3} - (9 y)^{3}$
$= (4 x - 9 y) {(4 x)^{2} + (9 y)^{2} + (4 x) \times (9 y)}$
$= (4 x - 9 y) (16 x^{2} + 81 y^{2} + 36 x y)$

Suggest Corrections

Factorise : 64x3−729y3

The correct option is A (4x−9y)(16x2+81y2+36xy) 64x3−729y3 =(4x)3−(9y)3 =(4x−9y){(4x)2+(9y)2+(4x)×(9y)} =(4x−9y)(16x2+81y2+36xy)

Factorise : $64 x^{3} - 729 y^{3}$

The correct option is A $(4 x - 9 y) (16 x^{2} + 81 y^{2} + 36 x y)$
$64 x^{3} - 729 y^{3}$
$= (4 x)^{3} - (9 y)^{3}$
$= (4 x - 9 y) {(4 x)^{2} + (9 y)^{2} + (4 x) \times (9 y)}$
$= (4 x - 9 y) (16 x^{2} + 81 y^{2} + 36 x y)$