CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise : 6a23a2bbc2+2c2

Open in App
Solution

6a23a2bbc2+2c2=6a23a2b+2c2bc2 (By grouping)=3a2(2b)+c2(2b)=(2b)(3a2+c2)


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon