The correct option is B 6(p 2q) #160; 6p 12q =2×3× p 2× 2×3× q =2×3(p 2q) =6(p 2q) ...

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Factorisation by Common Factors

Factorise 6...

Question

Factorise $6 p - 12 q$

(p - 2 q)

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6 (p - 2 q)

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6 (p - q)

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(p - q)

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Solution

The correct option is B $6 (p - 2 q)$
$6 p - 12 q$
$= 2 \times 3 \times p - 2 \times 2 \times 3 \times q$
$= 2 \times 3 (p - 2 q)$
$= 6 (p - 2 q)$

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6 p - 2 q = 8

Using properties of determinants, prove that:

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