MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Factorise: 6p...

Question

Factorise:

$6 p^{2} + 11 p - 10$

Open in App

Solution

$6 p^{2} + 11 p - 10 = 6 x^{2} + 15 x - 4 x - 10 ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} ∵ 6 \times (- 10) = 60 ∴ - 60 = 15 \times (- 4) 11 = 15 - 4 \end{matrix} ⎫ ⎪ ⎬ ⎪ ⎭ = 3 x (2 x + 5) - 2 (2 x + 5) = (3 x - 2) (2 x + 5) A n s .$

Suggest Corrections

thumbs-up

39

Similar questions

p^{2} - 11 p - 42

Q. Subtract:
−16p from −11p

32 \sum p = 1 (3 p + 2) {(10 \sum q = 1 (s i n \frac{2 q π}{11} - i c o s \frac{2 q π}{11}))}^{p}

Q. Subtract the second term form first term.

5 p, 11 p

(6 p^{2} + p - 12) \div (2 p + 3)

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Method of Common Factors

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorisation by Regrouping Terms

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon