Factorise : $7 b^{2} - 8 b + 1$

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Solution

$7 b^{2} - 8 b + 1 = 7 b^{2} - 7 b - b + 1 = 7 b (b - 1) - 1 (b - 1) = (b - 1) (7 b - 1)$

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Factorise $(a^{3} - 8 b^{3})$ .

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Factorise Completely : $a^{2} - 16 b^{2} - 2 a - 8 b$

a^{3} - 8 b^{3} - 64 c^{3} - 24 a b c

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