CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Factorise : 7...

Question

Factorise : $7 b^{2} - 8 b + 1$

Open in App

Solution

$7 b^{2} - 8 b + 1 = 7 b^{2} - 7 b - b + 1 = 7 b (b - 1) - 1 (b - 1) = (b - 1) (7 b - 1)$

Suggest Corrections

thumbs-up

5

Similar questions

Q. Factorise:

(1) 4a + 8b

Factorise $(a^{3} - 8 b^{3})$ .

Factorise:
$9 a^{2} + 3 a - 8 b - 64 b^{2}$

Factorise Completely : $a^{2} - 16 b^{2} - 2 a - 8 b$

a^{3} - 8 b^{3} - 64 c^{3} - 24 a b c

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Method of Common Factors

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorisation by Regrouping Terms

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon