Factorise 8−2(a−b)2
((2−a+b)(2+a−b))
2((2−a+b)(2+a−b))
2((2−a−b)(2+a−b))
((2−a−b)(a−b))
Given 8−2(a−b)2
⇒2(4−(a−b)2) ( Taking 2 common )
⇒2((2)2−(a−b)2)
⇒2(2−(a−b))(2+(a−b))
⇒2(2−a+b)(2+a−b)
Factorise : 8a3 + b3 + 12a2b + 6ab2
Factorise :
(a + b)3 - 8
My attempt
= (a + b)3 - (2)3
= (a + b - 2) {(a + b)2 + (2)2 + 2(a + b)}
What should I do not?