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Question

Factorise: 81x2198xy+121y2

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Solution

The given polynomial 81x2198xy+121y2 can be factorized as follows:

81x2198xy+121y2=(9x)2(2×9x×11y)+(11y)2=(9x11y)2((ab)2=a2+b22ab)

Hence, 81x2198xy+121y2=(9x11y)2.

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