Factorise: $81 x^{4} - 121 x^{2}$

Open in App

Solution

We need to factorize $81 x^{4} - 121 x^{2}$

Here taking $x^{2}$ common, we get

$x^{2} (81 x^{2} - 121)$

Using identity $a^{2} - b^{2} = (a - b) (a + b)$ , we have

$x^{2} (81 x^{2} - 121)$ $= x^{2} [(9 x)^{2} - (11)^{2}]$

$= x^{2} (9 x - 11) (9 x + 11)$

Hence, factors are $x^{2} (9 x - 11) (9 x + 11)$ .

Suggest Corrections

Similar questions

81 x^{4} - 121 x^{2}

81 x^{4} - 121 x^{2}

81 x^{4} - 16 y^{4}

3 x - \frac{1}{3 x} = 5

81 x^{4} + \frac{1}{81 x^{4}}

If $3 x - \frac{1}{3 x} = 5$ , find :

(i) $9 x^{2} + \frac{1}{9 x^{2}}$

(ii) $81 x^{4} + \frac{1}{81 x^{4}}$

Join BYJU'S Learning Program