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Question

Factorise 8a2−2x2


A

True

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B

False

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C

2(2ax)(2a+x)

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D

(2ax)(8a+x)

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Solution

The correct option is C

2(2ax)(2a+x)


Factorise 8a22x2

Given 8a22x2 = 2(4a2x2) ( taking 2 common)
= 2((2a)2(x)2) ( Getting in the form (a2b2)

= 2(2ax)(2a+x)


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