Factorise:
$9 (2 a - b)^{2} - 4 (2 a - b) - 13$

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Solution

$Let the value of 2 a - b be x. The equation becomes \Rightarrow 9 x^{2} - 4 x - 13 \Rightarrow 9 x^{2} - 13 x + 9 x - 13 \Rightarrow x (9 x - 13) + 1 (9 x - 13) \Rightarrow (x + 1) (9 x - 13) Putting value of x back to the equation \Rightarrow [2 a - b + 1] [9 (2 a - b) - 13] \Rightarrow [2 a - b + 1] [18 a - 9 b - 13]$

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