CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise 98(a+b)22

A
2[7a+7b+1][7a+b1]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2[7a7b+1][7a+b1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2[7a+7b1][7a+b1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2[7a+7b+1][7a+b+1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2[7a+7b+1][7a+b1]
98(a+b)22
=2[49(a+b)212]
=2[(7(a+b))212]
We know that,
{ a2b2=(a+b)(ab)}
=2[7a+7b+1][7a+7b1]

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon