wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise: 9a212ab+4b29m2+6mnn2

A
(3a2b3mn)(3a+2b3m+n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(3a+2b+3mn)(3a2b+3m+n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(3a2b+3mn)(3a2b3m+n)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (3a2b+3mn)(3a2b3m+n)
9a212ab+4b29m2+6mnn2
=9a212ab+4b2(9m26mn+n2)
=(3a2b)2(3mn)2
=(3a2b+3mn)(3a2b3m+n)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factors of a³ - b³
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon