9a^2 (a^2 4)^2 ⇒ ( 3a )^2 ( a^2 4a)^2 ⇒ ( 3a ( a^2 4 )) ( 3a + ( a^2 4 )) ⇒ ( 3a ( a^2 2^2 )) ( 3a + ( a^2 2^2 )) ⇒ ( 3a ( a 2) ( a ...

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Factorisation Using Algebraic Identities

Factorise: 9a...

Question

Factorise:

$9 a^{2} - (a^{2} - 4)^{2}$

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Solution

$9 a^{2} - (a^{2} - 4)^{2} \Rightarrow (3 a)^{2} - (a^{2} - 4 a)^{2} \Rightarrow (3 a - (a^{2} - 4)) (3 a + (a^{2} - 4)) \Rightarrow (3 a - (a^{2} - 2^{2})) (3 a + (a^{2} - 2^{2})) \Rightarrow (3 a - (a - 2) (a + 2)) (3 a + (a - 2) (a + 2))$

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Similar questions

Factorise:

$9 a^{2} + \frac{1}{9 a^{2}} - 2 - 12 a + \frac{4}{3 a}$

(a^{2})^{2} + 2 \times a^{2} \times 4 + 4^{2}

9 a^{2} - 6 a x

x^{2} + 6 a x + 9 a^{2}

Factorise:
$9 a^{2} - b^{2} + 4 b - 4$

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