Factorise: ${9 x}^{2} + 24 x + 16$

Open in App

Solution

$9 x^{2} + 24 x + 16$
$= 9 x^{2} + 12 x + 12 x + 16$
$= 3 x (3 x + 4) + 4 (3 x + 4)$
$= (3 x + 4) (3 x + 4)$
$= {(3 x + 4)}^{2}$

Suggest Corrections

Similar questions

Factorise: 9 x^{2} - 24 x + 16

zeroes of $9 x^{2} - 24 x + 16$

Factorise : $16 - 9 x^{2}$

(9 x^{2} - 24 x + 16)

(3 x - 4)

x^{3} - 9 x^{2} + 24 x - 16 = 0

Join BYJU'S Learning Program