Factorise : $9 x^{2} + 4 y^{2} + 1 + 12 x y + 4 y + 6 x$

Open in App

Solution

Now,
$9 x^{2} + 4 y^{2} + 1 + 12 x y + 4 y + 6 x$
$= 9 x^{2} + 12 x y + 4 y^{2} + 1 + 2 (2 y + 3 x)$
$= (3 x + 2 y)^{2} + 2 (3 x + 2 y) + 1$
$= (3 x + 2 y + 1)^{2}$ .

Suggest Corrections

Similar questions

9 x^{2} + 4 y^{2} + 16 z^{2} - 12 x y - 16 y z + 24 x z

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y + 16 y z + 24 x z

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y - 16 y z - 24 x z

Question 29
Factorise the following:

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y - 16 y z - 24 x z

25 x^{2} + 16 y^{2} + 4 z^{2} - 40 x y + 16 y z - 20 x z

16 x^{2} + 4 y^{2} + 9 z^{2} - 16 x y - 12 y z + 24 x z

9 x^{2} + 6 x y + y^{2}

4 y^{2} - 4 y + 1

x^{2} - \frac{y^{2}}{100}