Factorise:
$9 x^{2} y^{2} - 16$

(3 y + 4) (3 y - 4)

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(3 x y - 4) (3 x y - 4)

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(x y + 4) (3 x y - 4)

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(3 x y + 4) (3 x y - 4)

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Solution

The correct option is D $(3 x y + 4) (3 x y - 4)$
$9 x^{2} y^{2} - 16$
$= (3 x y)^{2} - (4)^{2}$
Using, $a^{2} - b^{2} = (a + b) (a - b)$
$= (3 x y + 4) (3 x y - 4)$

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