Question

Factorise: $a^2+10a+24$

Answer 1

We need to factorise $a^2+10a+24$

It can factorised by splitting middle term as

$a^2+10a+24=a^2+6a+4a+24$

$=a(a+6)+4(a+6)$

$=(a+6)(a+4)$

Thus factors are$(a+6),(a+4)$.