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Question

Factorise :
(a2−2a+3)(a2−2a+5)−35

A
(a22a+10)(a22a2)
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B
(a32a+5)(a22a4)
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C
(a22a+10)(a2a2)
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D
(a310a)(a22a4)
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Solution

The correct option is D (a22a+10)(a22a2)
(a22a+3)(a22a+5)35
=(a22a)2+5(a22a)+3(a22a)+1535
=(a22a)2+8(a22a)20
=(a22a)2+10(a22a)2(a22a)20
=(a22a)(a22a+10)2(a22a+10)
=(a22a+10)(a22a2)

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