Factorise :
$(a^{2} - 2 a + 3) (a^{2} - 2 a + 5) - 35$

(a^{2} - 2 a + 10) (a^{2} - 2 a - 2)

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(a^{3} - 2 a + 5) (a^{2} - 2 a - 4)

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(a^{2} - 2 a + 10) (a^{2} - a - 2)

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(a^{3} - 10 a) (a^{2} - 2 a - 4)

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Solution

The correct option is D $(a^{2} - 2 a + 10) (a^{2} - 2 a - 2)$
$(a^{2} - 2 a + 3) (a^{2} - 2 a + 5) - 35$
$= (a^{2} - 2 a)^{2} + 5 (a^{2} - 2 a) + 3 (a^{2} - 2 a) + 15 - 35$
$= (a^{2} - 2 a)^{2} + 8 (a^{2} - 2 a) - 20$
$= (a^{2} - 2 a)^{2} + 10 (a^{2} - 2 a) - 2 (a^{2} - 2 a) - 20$
$= (a^{2} - 2 a) (a^{2} - 2 a + 10) - 2 (a^{2} - 2 a + 10)$
$= (a^{2} - 2 a + 10) (a^{2} - 2 a - 2)$

Suggest Corrections

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(a^{2} - 2 a + 3) (a^{2} - 2 a + 5) - 35

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\sqrt{a^{2} + b} = a + \frac{b}{2 a +} \frac{b}{2 a +} \dots

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(\frac{a}{a^{2} - 4} - \frac{8}{a^{2} + 2 a}) \times \frac{a^{2} - 2 a}{4 - a} + \frac{a + 8}{a + 2}

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