Factorise $a^{2} + 5 a - 6$

(a - 6) (a + 1)

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(a + 6) (a - 1)

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(a + 6) (a + 1)

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(a + 3) (a - 2)

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Solution

The correct option is B $(a + 6) (a - 1)$
$a^{2} + 5 a - 6$

$= a^{2} + 6 a - a - 6$

$= a (a + 6) - 1 (a + 6)$

$= (a + 6) (a - 1)$

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