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Question

Factorise a2−81(b−c)2


A

(a+ 81b- 81c)(a-81b-81c)

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B

(a+ 9b- 9c)(a-9b-9c)

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C

(a+ 9b+9c)(a-9b-9c)

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D

(a-b+c)(a-b-c)

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Solution

The correct option is B

(a+ 9b- 9c)(a-9b-9c)


Given expression is a281(bc)2
= a2(9(bc))2
We know (a2b2) = (a+b)(ab)
= (a9(bc))(a+9(bc))
= (a9b+9c)(a+9b9c)


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