The correct option is A (a+4)^2 a^2+8a+ 16 = a^2+2 × a × 4 + 4^2 Using, nbsp; a^2+2ab +b^2= (a+ b)^2 = (a+ 4)^2 = (a+4)(a+4) ...

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(a + b)^2 Expansion and Visualisation

Factorise a...

Question

Factorise $a^{2} + 8 a + 16$

(a + 4)^{2}

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(a - 4) (a + 4)

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(2 a - 1)^{2}

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(a - 4)^{3}

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Solution

The correct option is A $(a + 4)^{2}$
$a^{2} + 8 a + 16$
$= a^{2} + 2 \times a \times 4 + 4^{2}$
Using, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$
$= (a + 4)^{2}$
$= (a + 4) (a + 4)$

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