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Question

Factorise:

a2+b2c2d2+2ab2cd

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Solution


a2+b2c2d2+2ab2cdrearrange the terms ,=a2+b2+2abc2d22cd=(a2+b2+2ab)(c2+d2+2cd)=(a+b)2(c+d)2=[(a+b)+(c+d)][(a+b)(c+d)]=(a+b+c+d)(a+bcd)


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