CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise:

a2+b2c2d2+2ab2cd

Open in App
Solution


a2+b2c2d2+2ab2cdrearrange the terms ,=a2+b2+2abc2d22cd=(a2+b2+2ab)(c2+d2+2cd)=(a+b)2(c+d)2=[(a+b)+(c+d)][(a+b)(c+d)]=(a+b+c+d)(a+bcd)


flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon