wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise: a2+1a2+32a2a

A
(a+1a1)(a1a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(a+1a1)(a+1a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(a+1a+1)(a+1a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(a+1a1)(a+1a1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D (a+1a1)(a+1a1)
a2+1a2+32a2a
=a2+1a2+1+22a2a
=(a)2+(1a)2+(1)2+2×a×1a+2×a×(1)+2×1a×(1)
(a+bc)2=a2+b2+c2+2ab2ac2cb
=(a+1a1)2=(a+1a1)(a+1a1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Division of an Expression by a Expression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon