Factorise :

$a^{2} b^{2} + 8 a b - 9$

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Solution

$a^{2} b^{2} + 8 a b - 9 = a^{2} b^{2} + 9 a b - a b - 9 = a b (a b + 9) - (a b + 9) = (a b + 9) (a b - 1)$

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a^{2} b^{2} + 8 a b - 9

a^{2} b^{2} + 8 a b - 9

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Factorise :

$a^{3} b - a^{2} b^{2} - b^{3}$

a^{2} b^{2} - 6 a b c + 9 c^{2}

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