We know a^3 + b^3 =(a+b) (a^2 ab +b^2) a^3+0.064= a^3+64/1000 = a^3+(4/10)^3 = (a+4/10) (a^2 4a/10+(4/10)^2) = (a+4/10) (a^2 4a/10+16/100) or a^3+0 ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation Using Algebraic Identities

Factorise: a3...

Question

Factorise:

$a^{3} + 0.064$

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Solution

$W e k n o w a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2}) a^{3} + 0.064 = a^{3} + \frac{64}{1000} = a^{3} + (\frac{4}{10})^{3} = (a + \frac{4}{10}) (a^{2} - \frac{4 a}{10} + (\frac{4}{10})^{2}) = (a + \frac{4}{10}) (a^{2} - \frac{4 a}{10} + \frac{16}{100}) o r a^{3} + 0.064 = 125 a^{3} + 8 = (5 a)^{3} + 2^{3} = (5 a + 2) (25 a^{2} - 10 a + 4)$

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Factorise: a3+0.064

We know a3+b3=(a+b)(a2−ab+b2)a3+0.064=a3+641000=a3+(410)3=(a+410)(a2−4a10+(410)2)=(a+410)(a2−4a10+16100)ora3+0.064=125a3+8=(5a)3+23=(5a+2)(25a2−10a+4)

Factorise:

$a^{3} + 0.064$