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Byju's Answer
Standard IX
Mathematics
Factorization of Expressions Reducible to Difference of Two Squares
Factorise a3-...
Question
Factorise
a
3
−
27
.
A
=
(
a
−
3
)
(
a
2
+
5
a
+
9
)
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B
=
(
a
+
3
)
(
a
2
+
5
a
+
9
)
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C
(
a
−
3
)
(
a
2
−
5
a
+
9
)
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D
(
a
−
3
)
(
a
3
+
5
a
+
9
)
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Solution
The correct option is
A
=
(
a
−
3
)
(
a
2
+
5
a
+
9
)
a
3
−
27
=
a
3
−
3
3
{
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
}
a
=
a
a
n
d
b
=
3
Hence
a
3
−
27
=
(
a
−
3
)
(
a
2
+
3
a
+
9
)
Suggest Corrections
31
Similar questions
Q.
Factorise:
3
a
2
−
5
a
+
2
Q.
If a matrix A is such that 3
A
3
+
2
A
2
+
5
A
+
I
=
0
,
then
A
-
1
equal to
(a)
-
3
A
2
+
2
A
+
5
(b)
3
A
2
+
2
A
+
5
(c)
3
A
2
-
2
A
-
5
(d) none of these
Q.
What is the remainder when
3
a
2
−
5
a
+
6
is divided by
a
−
2
?
Q.
Simplify
2
a
2
−
3
a
−
2
a
2
−
a
−
6
÷
3
a
2
−
5
a
−
2
3
a
2
−
8
a
−
3
, then the answer is
2
a
+
1
a
−
2
If true then enter
1
and if false then enter
0
Q.
Factorise:
a
4
+
5
a
2
+
9
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