Factorise
$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} - 8$

Open in App

Solution

$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} - 8$
$= (a + b)^{3} - (2)^{3}$
$= (a + b - 2) (a^{2} + b^{2} + 2 a b + 4 + 2 a + 2 b)$

Suggest Corrections

Similar questions

a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} - 8

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

Join BYJU'S Learning Program