Factorise (a3−8b3).
(a+2b)(a2+4ab+4b2)
(a−2b)(a2+2ab+4b2)
(a−2b)(a2−2ab+4b2)
(a+2b)(a2+2ab+4b2)
Given that a3−(2b)3 We know a3−b3 = (a−b)(a2+ab+b2) a3−(2b)3=(a−2b)(a2+(a)(2b)+(2b)2) = (a−2b)(a2+2ab+4b2)
Use the formula and find the product:
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