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Question

Factorise (a38b3).


A

(a+2b)(a2+4ab+4b2)

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B

(a2b)(a2+2ab+4b2)

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C

(a2b)(a22ab+4b2)

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D

(a+2b)(a2+2ab+4b2)

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Solution

The correct option is B

(a2b)(a2+2ab+4b2)


Given that a3(2b)3
We know a3b3 = (ab)(a2+ab+b2)
a3(2b)3=(a2b)(a2+(a)(2b)+(2b)2)
= (a2b)(a2+2ab+4b2)


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