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Question

Factorise: a3b3+c3

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Solution

Using the identity a3+b3=(a+b)(a2+b2ab)

Using the above identity, the expression a3b3+c3 can be factorised as follows:

a3b3+c3=(ab)3+(c)3=(ab+c)[(ab)2+(c)2(ab×c)]=(ab+c)(a2b2+c2abc)

Hence, a3b3+c3=(ab+c)(a2b2+c2abc)


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