CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise: a3b3+c3

Open in App
Solution

Using the identity a3+b3=(a+b)(a2+b2ab)

Using the above identity, the expression a3b3+c3 can be factorised as follows:

a3b3+c3=(ab)3+(c)3=(ab+c)[(ab)2+(c)2(ab×c)]=(ab+c)(a2b2+c2abc)

Hence, a3b3+c3=(ab+c)(a2b2+c2abc)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon