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B
(a2−2)(a+2)(a2+2)
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C
(a2−2)(a2+2)(a2+2)
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D
(a+11)(2a+12)(a2−12)
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Solution
The correct option is A(a−2)(a+2)(a2+4) a4−16 We know a2−b2=(a+b)(a−b) a4−16=(a2)2−(22)2 (a2)2−(4)2=(a2+4)(a−4) Factorizing further (a2+4)(a2−4)=(a2+4)(a−2)(a+2)